According to a campaign strategist for Rick Santorum, Mitt Romney doesn't have anywhere near the number of delegates that both his campaign and most media outlets report.
A memo by strategist John Yob, made public Friday morning, claims that the figures from the Associated Press used by both the New York Times and Wall Street Journal, are highly inaccurate. Those totals give Romney 658 delegates to Santorum's 281. Newt Gingrich and Ron Paul trail with 135 and 51, respectively.
Those numbers put Romney well over the halfway mark to the 1,144 delegates he needs to secure the nomination. But the Santorum memo projects that under certain contingencies, Romney can only count on 571 delegates to Santorum's 342, making the race considerably tighter.
Yob's assumption are very optimistic for Santorum, and assume the candidate could muster significant support from party bigwigs at the convention. His back-of-the-envelope match makes a few assumptions. Here are the three major ones:
The interactive delegate calculator that we debuted earlier this week treated Florida and Arizona as winner-take-all states, which they currently are. But to better examine the Santorum campaign's claim, below we've created a new version that makes those states proportional and makes Texas' 44 at-large delegates winner-take-all. We've also separated out unbound RNC delegates. You can allot those delegates as you wish using the slider at the top. The default figures represent current AP estimates for the so-called "super-delegates," who have publicly endorsed.
By our count, the optimistic assumptions by the Santorum camp should allot Romney 569 delegates to Santorum's 305--still a much better scenario for the former senator. We'll update this interactive after we hear back from Yob with the finer details of his assumptions.