Mets, Yoenis Cespedes reach 4-year, $110 million deal

The New York Mets have agreed to a four-year, $110 million deal with outfielder Yoenis Cespedes, sources told ESPN MLB Insider Jim Bowden on Tuesday.

Cespedes will receive a full no-trade clause and will make $22.5 million in 2017, $29 million in 2018 and 2019 and $29.5 million in 2020, sources told ESPN's Adam Rubin and Jerry Crasnick.

It's the top average annual value ever for an outfielder and ties the top AAV ever for a free-agent position player. It's the second-highest AAV for any position player behind Detroit's? Miguel Cabrera.

The story was first reported by FOX Sports.

Cespedes, 31, hit .280 and led the Mets with 31 home runs and 86 RBIs last season. He had received a three-year, $75 million deal from the Mets last offseason. That agreement gave him the right to opt out after collecting $27.5 million in 2016.

Including last season's haul, as well as a $100,000 bonus, his total deal with the Mets weighs in at $137.6 million over five seasons.

Since his debut with the Mets on Aug. 1, 2015, they went 106-74 with Cespedes in the starting lineup and 18-23 when he was not. The Mets have averaged 4.6 runs with him in the lineup, compared to 4.0 runs without him.

Cespedes was selected as an All-Star for the second time in his career in 2016, although he was unable to participate in the game because of a right quadriceps injury that lingered during the season's second half. He nonetheless reached the 30-homer plateau for the second time in his career, falling just shy of the combined 35 long balls he hit with the Tigers and Mets in 2015.

ESPN Mets reporter Adam Rubin contributed to this report.